C++ program to Count Even,Odd and zero's numbers from given array of N integers.

Q: Write a c++ program that will count the number of even,odd and zero's.

#include<iostream>
using namespace std;
int main()
{
    int n;
    cout<<"how many numbers : ";cin>>n;
    int num;
    int even=0,odd=0,zero=0;
     cout<<"\n\n";
     for(int i=0;i<n;i++)
     {
        cout<<"Enter "<<i+1<<" "<<"number  : ";
        cin>>num;
        switch(num%2)
        {
          case 0:
                if(num==0)
                 zero++;
                even++;
                break;
          case 1:
               odd++;
               break; 
default:
cout<<"Not a positive integer.\n"; 
break;          
        }     
     }
     cout<<" \n\t\tEVEN NUMBERS ARE  :\t"<<even;
     cout<<" \n\t\tODD NUMBERS ARE   :\t"<<odd;
     cout<<" \n\t\tZERO'S  ARE       :\t"<<zero;
     cout<<"\n\n\n";
     system("pause");
     return 0;
}